There is a clock at the bottom of the hill and a clock at the top of the hill. The clock at the bottom of the hill works fine but the clock at the top doesn't. How will you synchronize the two clocks. Obviously, you can't carry either of the clocks up or down the hill! And you have a horse to help you transport yourself. And, the time required for going up the hill is not equal to the time required to go down the hill.
Answer : You have to go up the hill and come back, with horse, without horse, getting four equations to solve four unknowns - time to go uphill - with horse, without horse, time to go downhill - with horse, without horse. Then you can go up the hill and set the clock to '(time when you left) + (time to go uphill with horse)'
1 comment:
Solution given for this puzzle is not correct as u do not know the time diff in two clocks which is actually the qn here.
So u can not simply do that as suggested.
I am posting here a solution posted by Munna at one of orkut communities.
Suppose top watch/clock is ahead by x minutes.
Because watch is not synchronised but we assume that it is working fine and not loosing or gaining time as no such condition is specified.
Then
suppose U is time for upward journey.
suppose D is time for downward journey.
Make three trips and note times from clocks.
Start from Bottome go up and come down. Note time in bottom clock.
Then U+D= T1( Difference in initial and Final time) --Pls note it is not a variable bit constant measured value.
Then go Up+Down+Up.
Note initial time in lower clock and final time in upper clock.
U +D+U+x= T2 ( Diff in final time in upper clock and initial time in lower clock)-Again a measured value.
Similarly go down +up+down.
Note final time in lower clock and initial time in upper clock.
Then D+U+D-x=T3 - Again a measured value.
Now u have three equations and three variables.
U can easily calculate, D, U and x.
Set the upper clock after finding value of x.
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